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Let's see if Marlboro male students
are taller than female students.
Method: difference of means
m1 = mean of male heights
m2 = mean of femail heights
H0 : males and females are the same height
diff = m1-m2 = 0
Halpha: males are taller (one tail)
m1 > m2
Standard deviation of m1 is
sigma_m1 = 2.94 / sqrt(41) = 0.459
(This is also called the "Standard Error").
Standard deviation of m2 is
sigma_m2 = = 3.42/sqrt(44) = 0.516
Standard deviation of difference is
sigma_diff = sqrt( sigma_m1^2 + sigma_m2^2)
= sqrt( 0.459^2 + 0.516^2)
= 0.691
Let's choose alpha significance level = 0.01.
Then our cutoff value for diff is where the
probability of diff > cutoff is 0.01.
One way to find the cutoff is to calculate
the z-score, then look in our textbook table D-4,
then convert back to a corresponding raw score.
Another is to use Excel's NORMINV function.
Type =NORMINV(0.99,0,0.691) into a cell,
hit return, and get cutoff
= 1.61. In other words,
a normal variable with mean=0 and sigma=0.691
is bigger than 1.61 only 1% of the time.
Therefore, our decision rule is to reject the
null hypothesis if m1-m2 > 1.61.
The actual value is
diff = m1-m2 = mean male - mean female
= 70.86 - 64.64 = 6.22
and so we *do* reject the null hypothesis:
Male students at Marlboro are taller than female students.
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