/* e_calc.c
 * computes e to a user specified degree of precision
 * 
 * King Chapter 6, Ex. 11.
 * The number e may be expressed as an infinite series
 * 1 + 1/1 + 1/(2!) + 1/(3!) + 1/(4!)...
 * 
 * By Cory Spitzer
 * March 23th, 2013
 * 
 * 
 */

#include <stdio.h>

int main(void){
    float modifier;
    float divisor = 1, e = 1;
    int number, index, sub_index;
    // char mod_string;
    
    printf("Enter an integer to compute e\n ");
    printf("higher numbers produce more precision: ");
    scanf("%i", &number);
    
    for (index = 1; index <= number; index++){
        for (sub_index = index; sub_index <= number; sub_index++){
            divisor = divisor....;
        }
        modifier = 1/divisor;
        // sprintf(mod_string,"1/%d", )
        printf("The modifier for the round %d is 1/%f\n", index, divisor);
        e += modifier;
        printf("e = %f\n", e);
    }
    printf("e = %f\n", e);
    
    return 0;
}