/* words1.c
 *
 * read and write a list of words
 * (assigment for Feb 6 from http://cs.marlboro.edu/courses/spring2013/systems)
 *
 * version 1 : quick and dirty: 
 *   - One big block of memory for word list
 *   - Hard-coded constants.
 *   - No error checking.
 *   - Word entry terminated by word = '-'
 *
 * This code works (within the size bounds) but is not what I'd call
 * good practice. Input with too many characters or words will bleed
 * into the the next word, or overflow the allocated space and
 * possibly crash the program.
 *
 *    $ gcc word1.c -o words1
 *    $ ./words1
 *    Enter words separated by whitespace or newline. Type - to stop.
 *    one
 *    two
 *    three
 *    -
 *    The words are [one two three ].
 *
 *    $ ./words1
 *    Enter words separated by whitespace or newline. Type - to stop.
 *    thiswordistoolong
 *    two
 *    three
 *    The words are [thiswordtwo two three ].
 *
 * Jim Mahoney | Feb 2013 | MIT License
 */

#include <stdio.h>

int main(){
  char buffer[5*8];          // space for 5 words of 8 characters each
  char* word = buffer;       // a pointer to one of the words
  int n_words = 0;           // number of words read.

  printf("Enter words separated by whitespace or newline. Type - to stop.\n");
  while (1){
    scanf("%s", word);
    if (word[0] == '-') break;
    word += 8;
    n_words++;
  }

  word = buffer;
  printf("The words are [");
  while (n_words--){
    printf("%s ", word);
    word += 8;
  }
  printf("].\n");

  return 0;
}