Jim's
Tutorials

Wrote some code in an organized fashion to solve euler 6:

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

• I started by brute forcing a simple loop then refactored into an object and some tests. Possibly a little backward but works for me.

attachments

		last modified	size
	euler6.py	Sat Apr 27 2024 05:17 am	1.0K
	euler_6_test.py	Sat Apr 27 2024 05:17 am	350B