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Modern
Physics

Spring 2018
course
site

April 2

Go over chapter 6 homework.

Start chapter 7.

The text does not do a good job of explaining where the solution to the 3D Schrodinger comes from. I've added a section to the references with links to more complete explanations - please check those out.

energy in rotating coords

E=12m(vx2+vy2)C/r=12m(vr2+vθ2)C/r

where vθ is the velocity around the origin and C/r is some central potential.

Since the angular momentum is L=r(mvθ) and is unchanging, we can also write this as

E=12m(vr2+L2m2r2)C/r=12mvr2+L22mr2C/r

Those last two terms can be thought of as an "effective potential" for radial motion in a rotating coordinate system.

Compare this with the radial part of the 3d schrodinger equation.

https://cs.marlboro.college /cours /spring2018 /modern_physics /notes /apr2
last modified Thu April 17 2025 11:55 pm